Find the value of a3−b3−3a2b+3ab2 , when a = 5 and b = 3.
8
a3−b3−3a2b+3ab2, the given expression is the expansion of (a−b)3
So, we have to put the values of the a = 5 and b = 3 in the given expansion
=a3−b3−3a2b+3ab2=(a−b)3=(5−3)3=23=8
Alternate method;
Substitute the value of a and b equal to 5 and 3 respectively in the expression a3−b3−3a2b+3ab2
= 53−33−3(5)2b+3(5)(2)2
= 8