Given system of equations is:
2x + 3y = 7 and
2ax + ay = 28 - by
The above equations can be rewritten as:
2x + 3y - 7 = 0 and
2ax + (a + b)y - 28 = 0
Here the system must have infinite solutions. We know that, for the given system of equations to have infinitely many solutions,
a1/a2 = b1/b2 = c1/c2
i.e
2/2a = 3/(a+b) = -7/-28
1/a = 3/(a+b) = 1/4
1/a = 1/4
a = 4
3/(a+b) = 1/4
a+b = 12
4+b = 12
b = 8