Find the value of A and B.
A 1
+ 1 B
---------------------
B 0
----------------------

A = 7, B = 2

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A = 7, B = 9

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A = 8, B = 9

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A = 7, B = 3

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Solution

The correct option is B $A = 7, B = 9$
From the equation we get,
$B + 1 = 0$ ....(i)
and, $A + 1 +$ carry-over $= B$ .....(ii)
Now, $B$ must be equal to $9$ from equation (i) to make the sum $0$
Then, carry-over will be $1$
hence, $A + 1 + 1 = 9$
or, $A = 7$
Therefore, $71 + 19 = 90$

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Similar questions

$(7 a^{2} - 63 b^{2}) = ? (a) (7 a - 9 b) (9 a + 7 b) (b) (7 a - 9 b) (7 a + 9 b) (c) 9 (a - 3 b) (a + 3 b) (d) 7 (a - 3 b) (a + 3 b)$

Q. Tick (✓) the correct answer:
(7a² − 63b²) = ?
(a) (7a − 9b)(9a + 7b)
(b) (7a − 9b)(7a + 9b)
(c) 9(a − 3b)(a + 3b)
(d) 7(a − 3b)(a + 3b)

Q. If

U = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}

A = {0, 3, 4, 7}

B = {1, 2, 8, 9}

then

(A U B)^{'}

If
A = {1, 2, 3, 4}

B = {3, 4, 5, 6, 7}

C = {6, 7, 8, 9}

D = {7, 8, 9, 10}

$\begin{matrix} C o l u m n A & C o l u m n B 1. A \cup B & a . {3, 4, 6, 7} 2. A \cap B & b . \emptyset 3. (B \cap C) \cup D & c . {3, 4} 4. B \cup C \cup D & d . {3, 4, 5, 6, 7, 8, 9, 10} 5. (A \cap B) \cap (B \cup C) & e . {1, 2, 3, 4, 5, 6, 7} f . {6, 7, 8, 9, 10} g . {7} \end{matrix}$

Q. Let set U = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10}, set A = {2, 4, 6, 8}, and set B = {1, 3, 5, 7, 9}. Prove that (A

\cap

B)’ = A’

\cup

B.’

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Find the value of A and B. A 1 + 1 B--------------------- B 0----------------------

The correct option is B A=7,B=9From the equation we get,B+1=0....(i)and, A+1+ carry-over =B .....(ii)Now, B must be equal to 9 from equation (i) to make the sum 0Then, carry-over will be 1hence, A+1+1=9or, A=7Therefore, 71+19=90

Find the value of A and B.
A 1
+ 1 B
---------------------
B 0
----------------------

The correct option is B $A = 7, B = 9$
From the equation we get,
$B + 1 = 0$ ....(i)
and, $A + 1 +$ carry-over $= B$ .....(ii)
Now, $B$ must be equal to $9$ from equation (i) to make the sum $0$
Then, carry-over will be $1$
hence, $A + 1 + 1 = 9$
or, $A = 7$
Therefore, $71 + 19 = 90$