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Question

Find the value of a And b,if the line 5bx-3ay=30 passes through (-1,0) and (0,-3)

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Solution

Given line
5bx-3ay=30
Since it passes through (-1,0)
and (0,-3)
​​​​So this point should satisfy the equatiom
Substituting in (-1,0)
We get
5b(-1)-3a(0)=30
-5b=30
b=-6
Now substituting (0,-3)
We get
5b(0)-3a(-3)=30
9a=30
a=30/9
=10/3

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