Find the value of a And b,if the line 5bx-3ay=30 passes through (-1,0) and (0,-3)
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Solution
Given line 5bx-3ay=30 Since it passes through (-1,0) and (0,-3) So this point should satisfy the equatiom Substituting in (-1,0) We get 5b(-1)-3a(0)=30 -5b=30 b=-6 Now substituting (0,-3) We get 5b(0)-3a(-3)=30 9a=30 a=30/9 =10/3