F(x)=x⁴+ax³+2x²-3x+b
x+1=0 or x=-1.
f(-1)=(-1)⁴+a(-1)³+2(-1)²-3(-1)+b
=1-a+2+3+b
=6-a+b
(x+1) is a factor, Therefore reminder=0.
6-a+b=0 Or -a+b=-6 -- (eq1)
Again (x-1)=0 or x=1
f(1) = (1)⁴+a(1)³+2(1)²-3(1)+b
=1+a+2-3+b
=a+b=0 -- (eq2)
Adding 1&2
2b=-6
b=-3
From 2,
a=3
a=3, b=-3