Find the value of A - B2 given that x- 4- A2 - x2 - 12x - 36 and B2 - 4x2 - 28x - 49

The correct option is E 9x^2 6x + 1 A^2 = x^2+12x+36 = (x+6)^2 #160; ⇒ A = |x+6| B^2 = 4x^2 28x+49 = (2x 7)^2 #160; ⇒ B = |2x 7| ...

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Range of Quadratic Expression

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Question

Find the value of $(A + B)^{2}$ given that $x \geq 4, A^{2} = x^{2} + 12 x + 36$ and $B^{2} = 4 x^{2} - 28 x + 49$

2 x^{2} + 5 x + - 42

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3 x^{2} - 9 x - 1

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4 x^{2} - x + 13

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5 x^{2} - 26 x + 85

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9 x^{2} - 6 x + 1

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\frac{4 x^{2} + 15 x + 17}{x^{2} + 4 x + 12} = \frac{5 x^{2} + 16 x + 18}{2 x^{2} + 5 x + 13}

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