Find the value of A+B+C+D+E+F in the given magic hexagon.
(3 Marks)

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Solution

As we know in a magic hexagon the number in rectangle is product of the adjacent numbers in circle.
So,

$A = 4 \times 15 = 60 B = 15 \times 12 = 180 C = 12 \times 13 = 156 D = 13 \times 10 = 130 E = 10 \times 16 = 160 F = 16 \times 4 = 64$ (2 Marks)

Hence A+B+C+D+E+F
=60+180+156+130+160+64
=750
(1 Marks)

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Find the value of A+B+C+D+E+F in the given magic hexagon. (3 Marks)

As we know in a magic hexagon the number in rectangle is product of the adjacent numbers in circle. So, A=4×15=60B=15×12=180C=12×13=156D=13×10=130E=10×16=160F=16×4=64 (2 Marks) Hence A+B+C+D+E+F =60+180+156+130+160+64 =750 (1 Marks)

Find the value of A+B+C+D+E+F in the given magic hexagon.
(3 Marks)