Find the value of a + b, if a $x^{2}$ + bx + c = $(2 x - 1)^{2}$ is an identity.

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Solution

a $x^{2}$ + bx + c = 4 $x^{2}$ - 4x + 1, for it to be an identity,

a = 4, b = -4

a + b = 4 - 4 = 0

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