Question

Find the value of $a$:

$\frac{6}{3a}+\frac{10}{3a}=256$

Answer 1

Given $\frac{6}{3a}+\frac{10}{3a}=256$

$\Rightarrow \frac{16}{3a}=256$

$\Rightarrow 3a=\frac{16}{256}$

$\Rightarrow 3a=\frac{1}{16}$

$\therefore a=\frac{1}{48}$