Find the value of 'a' for which the following points A(a, 3), B(2, 1) and C(5, a) are collinear. [2Marks]
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Solution
Points A(a, 3), B(2, 1) and C(5, a) are collinear
Points A,B,C lie on the same line ∴ Slope of AB = Slope of BC [1Mark] ⇒1−32−a=a−15−2 ⇒−22−a=a−13 ⇒2a−2=a−13 ⇒6=a2−3a+2 ⇒a2−3a−4=0 ⇒(a−4)(a+1)=0
Either a−4=0 or a+1=0 ⇒a=4 or a=−1 [1Mark]