Find the value of 'a' for which the following points A(a, 3), B(2, 1) and C(5, a) are collinear.
a=4 or a=−1
Points A(a, 3), B(2, 1) and C(5, a) are collinear.
∴ Slope of AB = Slope of BC
⇒1−32−a=a−15−2
⇒−22−a=a−13
⇒2a−2=a−13
⇒6=a2−3a+2
⇒a2−3a−4=0
⇒(a−4)(a+1)=0
Either a−4=0 or a+1=0
⇒ a=4 or a=−1.