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Question

Find the value of a for which the vector ¯¯¯¯A=3^i+3^j+9^k and ¯¯¯¯B=^i+a^j+3^k are parallel.

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Solution

Given A=3^i+3^j+9^k and B=^i+a^j+3^k
Given , Vectors are parallel so A×B=0
(3^i+3^j+9^k)×(^i+a^j+9^k)=(99a)^i+(99)^j+(3a3)^k=0
a=1

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