Find the value of a given polynomial at the indicated value of variables.
$q (y) = 3 y^{2} - 4 y \sqrt{11} + 8 \sqrt{11}$ at $y = 2$

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Solution

Given : $q (y) = 3 y^{2} - 4 y \sqrt{11} + 8 \sqrt{11}$

$q (2) = 3 \times 2^{2} - 4 \times 2 \sqrt{11} + 8 \sqrt{11}$

$= 3 \times 4$

$= 12$

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q (y) = 3 y^{2} - 4 y + \sqrt{11}

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