Find the value of ‘a’, if the line through (–2, 3) and (8, 5) is perpendicular to y = ax + 2

- 5

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\frac{1}{5}

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\frac{- 1}{5}

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5

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Solution

The correct option is A $- 5$
$Let m_{1} be slope of line joining (- 2, 3) and (8, 5) Let m_{2} be slope of y = ax + 2 \Rightarrow m_{1} = \frac{5 - 3}{8 + 2} = \frac{1}{5} and m_{2} = a We know that two lines with slopes m_{1} and m_{2} are perpendicular to each other if m_{1} \times m_{2} = - 1 \Rightarrow \frac{1}{5} \times a = - 1 \Rightarrow a = - 5$

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Find the value of ‘a’, if the line through (–2, 3) and (8, 5) is perpendicular to y = ax + 2

The correct option is A −5Let m1 be slope of line joining (−2, 3) and (8, 5) Let m2 be slope of y = ax + 2⇒m1=5−38+2=15 and m2=a We know that two lines with slopes m1 and m2 are perpendicular to each other if m1×m2=−1⇒15×a=−1⇒a=−5