Question

Find the value of a if the roots of the equation $x^2-2ax+27=0$ are $\alpha ,3\alpha$ and $\alpha >$ 0

• A. 6
• B. 12
• C. -6
• D. -12

Answer 1

The correct option is A

6

$3\alpha$ X $\alpha$ = 27
$\Rightarrow {\alpha }^2$ = 9
$\alpha =3(\alpha >0=>ca{n}^{\prime }tbe-3)$
$\alpha +3\alpha =2a$
$\Rightarrow 2a=4\alpha$
$a=2\alpha$
= 2 x 3
= 6