Question

Find the value of $a$, if $(x-a)$ is a factor of the polynomial, $x^6-a{x}^5+x^4-a{x}^3+3x-a+2$=0.

• A. $-1$
• B. $1$
• C. $-2$
• D. $2$

Answer 1

Answer: (A)

$-1$

Since $(x-a)$ is the factor of the given polynominal,

$⟹x=a$ is the zeros of the polynomial.

$\therefore$ By putting $x=a$ we get,

$⟹a^6-a{a}^5+a^4-a{a}^3+3a-a+2=0$

$⟹2a+2=0$

$⟹a=-1$