Find the value of A in the addition.
A+A+AB A
5
This has two letters A and B whose values are to be found.
Study the addition in the ones column: the sum of three A's is a number whose ones digit is A.
Therefore, the sum of two A's must be a number whose ones digit is 0.
This happens only for A = 0 and A = 5.
If A = 0, then the sum is 0 + 0+ 0 = 0, which makes B = 0 too.
We do not want this (as it makes A = B, and then the tens digit of BA too becomes 0),
Also we can check these using algebric expression.
3A=10×B+A
⇒ 2A=10×B
⇒B=A5
The above solution satisfies this relation. So, A = 5.
Therefore, the puzzle is solved as shown below.
5+5+51 5
That is, A= 5 and B= 1