i ) It is given that ,
( 3 , a ) lies on the line 2x - 3y + 5 = 0
Substitute x = 3 , y = a in the equation
We get ,
2 × 3 - 3 a + 5 = 0
6 - 3a + 5 = 0
11 - 3a = 0
11 = 3a
11/3 = a. (answer)
If your question is 2x-3y-5=0 then
i ) It is given that ,
( 3 , a ) lies on the line 2x - 3y - 5 = 0
Substitute x = 3 , y = a in the equation
We get ,
2 × 3 - 3a - 5 = 0
6 - 3a - 5 = 0
1 - 3a = 0
1 = 3a
1/3 = a