Find the value of $a$ which satisfies $16 a^{2} + 4 a - 6 = 0$

- 0.75

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- 0.5

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0

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1

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Solution

The correct option is B $- 0.75$
Given, $16 a^{2} + 4 a - 6 = 0$
$\Rightarrow 8 a^{2} + 2 a - 3 = 0$
$\Rightarrow 8 a^{2} + 6 a - 4 a - 3 = 0$
$\Rightarrow a (3 a + 4) + 1 (3 a + 4) = 0$
$\Rightarrow (4 a + 3) (2 a - 1) = 0$
Than $4 a + 3 = 0$ or $a = - 0.75$
And $2 a - 1$ or $a = 0.5$

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