Find the value of a3-6 a p- p3-8 when p-2-a

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Question

Find the value of a³+6ap+p³-8 when p=2-a

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p = (2 - a)

a^{3} + 6 a p + p^{3} - 8

p = 2 - a

a^{3} + 6 a p + p^{3} - 8 = 0

a^{3} + b^{3} + 6 a b - 8

a + b = 2.

If the value of $(\frac{a^{3} - b^{3}}{a^{3} + b^{3}})$ when a = 7 and b = 2 is $\frac{335}{p}$ , then p is 321.

If the value of $(\frac{a^{3} - b^{3}}{a^{3} + b^{3}})$ , when $a = 7$ and $b = 2$ is $\frac{335}{p}$ , then $p$ is $321$ .

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