Find the value of $A C$ (in cm) for given figure.

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Solution

Given: $A B = 12$ , $∠ A C B = 30^{\circ}$
Now, $sin 30 = \frac{P}{H} = \frac{A B}{A C}$

$\frac{1}{2} = \frac{12}{A C}$ $\Rightarrow A C = 24$

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Find the value of AC (in cm) for given figure.

Given: AB=12, ∠ACB=30∘Now, sin30=PH=ABAC12=12AC ⇒AC=24

Find the value of $A C$ (in cm) for given figure.

Given: $A B = 12$ , $∠ A C B = 30^{\circ}$
Now, $sin 30 = \frac{P}{H} = \frac{A B}{A C}$

$\frac{1}{2} = \frac{12}{A C}$ $\Rightarrow A C = 24$