Question

# Find the value of acceleration due to gravity near the surface of the earth.

Solution

## We know that, mg=GMmr2 Here, m = Mass of the body g = Acceleration due to gravity M = Mass of the Earth = 5.98×1024 kg G = Universal gravitational constant = 6.673×10−11Nm2kg−2 r = Radius of the Earth = 6.38×106 m So,  g=GMr2=6.673×10−11×5.98×1024(6.38×106)2=9.8m/s2

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