Question

Find the value of acceleration due to gravity on the surface of the moon. Maa of the moon is $7.35\times {10}^{22}Kg$. The radius of the moon in$1.74\times {10}^{6}m$ and G is $6.67\times {10}^{-11}$.

Answer 1

Step 1: Given Data :

Mass of the moon(M) = $7.35\times {10}^{22}Kg$

The radius of moon, R =$1.74\times {10}^{6}m$

Universal gravitational constant = $6.67\times {10}^{-11}$

we need to calculate Acceleration due to gravity(g).

Step 2: Formula used :
$g=G\frac{M}{R^2}$

Step 3: Calculating gravitational force :

$g=6.67\times {10}^{-11}\times \frac{7.35\times {10}^{22}}{{(1.74\times {10}^6)}^2}=1.62m/s^2$

Hence, acceleration due to gravity(g) is $1.62m/s^2$.