Find the value of $∠ A C B$ in the figure shown below:

80 $^{\circ}$

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60 $^{\circ}$

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70 $^{\circ}$

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40 $^{\circ}$

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Solution

The correct option is D
40 $^{\circ}$

We know that, $∠ A B C + ∠ C A B + ∠ A C B = 180^{\circ}$ [Angle sum property]

$90^{\circ} + 50^{\circ} + ∠ A C B = 180^{\circ} ∠ A C B = 180^{\circ} - 140^{\circ} ∠ A C B = 40^{\circ}$

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Find the value of ∠ACB in the figure shown below:

The correct option is D 40∘ We know that,∠ABC+∠CAB+∠ACB=180∘ [Angle sum property] 90∘+50∘+∠ACB=180∘∠ACB=180∘−140∘∠ACB=40∘

Find the value of $∠ A C B$ in the figure shown below:

The correct option is D
40 $^{\circ}$

We know that, $∠ A B C + ∠ C A B + ∠ A C B = 180^{\circ}$ [Angle sum property]

$90^{\circ} + 50^{\circ} + ∠ A C B = 180^{\circ} ∠ A C B = 180^{\circ} - 140^{\circ} ∠ A C B = 40^{\circ}$