Find the value of - ADC -A- 153-B- 143-C -147-D- None of these

The correct option is B 143° In ΔAED, ED = BC = 15 cm sin A = ED/AD sin A = 15/25 = 3/5 sin A = 37^∘ Since, sum of all interior angles of an quadrilaterals i ...

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Standard IX

Mathematics

Angle Subtended by Diameter on the Circle

Find the valu...

Question

Find the value of $∠$ ADC.

153°

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143°

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147°

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None of these

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Solution

The correct option is B
143°

In $Δ$ AED, ED = BC = 15 cm

sin A = $\frac{E D}{A D}$

sin A = $\frac{15}{25}$

= $\frac{3}{5}$

sin A = $37^{\circ}$

Since, sum of all interior angles of an quadrilaterals is $360^{\circ}$

∠ADC = $360^{\circ}$ - $(90^{\circ} + 90^{\circ} + 37^{\circ})$

= $143^{\circ}$

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Find the value of ∠ADC.

The correct option is B 143° In ΔAED, ED = BC = 15 cm sin A = EDAD sin A = 1525 = 35 sin A = 37∘ Since, sum of all interior angles of an quadrilaterals is 360∘ ∠ADC = 360∘ - (90∘+90∘+37∘) = 143∘

Find the value of $∠$ ADC.