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Question

Find the value of AEB in the given figure.

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Solution


T.P.TAEB=60
CD =radius
ΔAOC,ΔBOD are isosceles Δ Triangle.
ΔCOD is an equilateral Δ Triangle
1802x+60+1802y=180
2x+2y=240
x+y=120
In ΔAEB,x+y=AEB=180(x+y)=180120=60


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