Find the value of ∠BAC in the given figure if AB = AC.
4x
x
5x
7x
2x
Δ ABO ≅ΔACO,
∠ABO = ∠ACO = x
∠ABO = ∠BAO = x ΔABO is isosceles
∠ACO = ∠CAO = x ΔACO is isosceles
So, ∠BAC = 2x