Find the value of angles a and b in the following figure.
a = 110∘ [Vertically opposite angles]
b = 180∘– a [Interior angles on the same side of transversal]
= 180∘– a
= 180∘ – 110∘
= 70∘
In the given figure PQ || RS ∠PAB=70∘ , ∠ACS=110∘ , then ∠BAC=