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Byju's Answer
Standard XII
Mathematics
Fundamental Laws of Logarithms
find the valu...
Question
find the value of
[1] log
10
5 * log
10
20 + (log
10
2)
2
[2] 5
log
(5^1/2)
2
+ 9
log
3
7
+ 8
log
2
5
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Solution
Dear
Student
,
log
10
5
×
log
10
20
+
log
10
2
2
=
log
10
5
×
log
10
2
×
10
+
log
10
2
2
=
log
10
5
×
1
+
log
10
2
+
log
10
2
2
=
log
10
5
+
log
10
5
log
10
2
+
log
10
2
2
=
log
10
5
+
log
10
2
log
10
5
+
log
10
2
=
log
10
5
+
log
10
2
log
10
5
×
2
=
log
10
5
+
log
10
2
log
10
10
=
log
10
5
+
log
10
2
=
log
10
5
×
2
=
log
10
10
=
1
2
)
5
log
5
1
2
2
+
3
2
log
3
7
+
2
3
log
2
5
=
5
2
log
5
2
+
3
2
log
3
7
+
2
3
log
2
5
=
5
log
5
2
2
+
3
log
3
7
2
+
2
log
2
5
3
=
2
2
+
7
2
+
5
3
=
4
+
49
+
125
Regards
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0
Similar questions
Q.
Find the value of
log
10
5.
log
10
20
+
(
log
10
2
)
2
Q.
Solve
5
l
o
g
√
5
2
+
9
l
o
g
3
7
−
8
l
o
g
2
5
Q.
The value of
log
10
5
⋅
log
10
20
+
(
log
10
2
)
2
is
Q.
If
log
10
[
1
2
x
+
x
−
1
]
=
x
[
log
10
5
−
1
]
, then
x
equals to
Q.
If
log
10
[
1
2
x
+
x
−
1
]
=
x
[
(
log
10
5
)
−
1
]
, then
x
is equal to
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