Question

Find the value of $\frac{\tan {47}^0}{\cot {43}^0}$

Answer 1

We have, $\frac{\tan \left({47}^{\circ }\right)}{\cot \left({43}^{\circ }\right)}$

$=\frac{\tan ({90}^{\circ }-{43}^{\circ })}{\cot {43}^{\circ }}$

$=\frac{\cot {43}^{\circ }}{\cot {43}^{\circ }}=1$