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Byju's Answer
Standard XII
Mathematics
Domain and Range of Basic Inverse Trigonometric Functions
Find the valu...
Question
Find the value of
cos
−
1
(
cos
13
)
Open in App
Solution
cos
−
1
(
cos
13
)
∈
[
0
,
π
]
and we know ,
cos
(
θ
+
2
π
)
=
cos
(
2
π
−
θ
)
=
cos
(
θ
−
2
π
)
=
cos
θ
∴
cos
−
1
(
cos
13
)
=
cos
−
1
(
cos
(
13
−
4
π
)
)
=
13
−
4
π
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0
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