Find the value of
$cos 270^{o}$

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Solution

$cos 270^{\circ} = cos (180^{\circ} + 90^{\circ})$
$180^{\circ} + θ$ is in third quadrant.By ASTC rule, $cos θ$ is negative in third quadrant.
Hence $cos (180^{\circ} + 60^{\circ}) = cos 90^{\circ} = 0$

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