Find the value of (cosθ+isinθ)n where θϵR,nϵI,i=√−1
A
n(cosθ+isinθ)
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B
ncosθ+isinnθ
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C
cosnθ+isinnθ
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D
cosnθ+insinθ
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Solution
The correct option is Ccosnθ+isinnθ Given (cosθ+isinθ)n…… (1)
We know eiθ=cosθ+isinθ
We can replace in equation (1)
From equation 1 we get, (eiθ)n
=einθ
This can be written as (cosnθ+isinnθ)