Find the value of 2 30-2 cos 2 60-3-4 2 45-4 sin 2 30-

The correct options are A 0 B sin 0^∘ + cos 90^∘ nbsp; nbsp;cot^2 30^∘ 2cos^2 60^∘ 3/4sec^2 45^∘ 4sin^2 30^∘ = (√(3))^2 2(1/2)^2 3/4(√(2))^2 4(1/2)^2 = ...

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Byju's Answer

Standard IX

Mathematics

Trigonometric Ratios of Standard Angles

Find the valu...

Question

Find the value of
$c o t^{2} 30^{\circ} - 2 c o s^{2} 60^{\circ} - \frac{3}{4} s e c^{2} 45^{\circ} - 4 s i n^{2} 30^{\circ} .$

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$s i n 0^{\circ} + c o s 90^{\circ}$

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$s i n 90^{\circ} + c o s 0^{\circ}$

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Solution

The correct options are
A
0

B
$s i n 0^{\circ} + c o s 90^{\circ}$

$c o t^{2} 30^{\circ} - 2 c o s^{2} 60^{\circ} - \frac{3}{4} s e c^{2} 45^{\circ} - 4 s i n^{2} 30^{\circ}$

$= (\sqrt{3})^{2} - 2 (\frac{1}{2})^{2} - \frac{3}{4} (\sqrt{2})^{2} - 4 (\frac{1}{2})^{2}$
$= 3 - \frac{1}{2} - \frac{3}{2} - 1 = 0$

Also, the value of
sin 0° + cos 90° = 0 + 0 = 0

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Similar questions

The value $c o t^{2} 30^{\circ} - 2 c o s^{2} 60^{\circ} - \frac{3}{4} s e c^{2} 45^{\circ} - 4 s i n^{2} 30^{\circ}$ is

Q. Find the value of

c o t^{2} 30^{\circ} - 2 c o s^{2} 60^{\circ} - \frac{3}{4} s e c^{2} 45^{\circ} - 4 s i n^{2} 30^{\circ} .

$c o t^{2} 30^{\circ} - 2 c o s^{2} 30^{\circ} - \frac{3}{4} s e c^{2} 45^{\circ} + \frac{1}{4} c o s e c^{2} 30^{\circ}$

$(s i n^{2} 30^{\circ} + 4 c o t^{2} 45^{\circ} - s e c^{2} 60^{\circ}) (c o s e c^{2} 45^{\circ} s e c^{2} 30^{\circ})$

Q. Evaluate each of the following

(cosec² 45° sec² 30°) (sin² 30° + 4 cot² 45° − sec² 60°)

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Find the value of cot2 30∘−2cos2 60∘−34sec2 45∘−4sin2 30∘.

The correct options are A 0 B sin0∘+cos90∘ cot2 30∘−2cos2 60∘−34sec2 45∘−4sin2 30∘ =(√3)2−2(12)2−34(√2)2−4(12)2 =3−12−32−1=0 Also, the value of sin 0° + cos 90° = 0 + 0 = 0

Find the value of
$c o t^{2} 30^{\circ} - 2 c o s^{2} 60^{\circ} - \frac{3}{4} s e c^{2} 45^{\circ} - 4 s i n^{2} 30^{\circ} .$