Find the value of cot2x-1sin2x

The correct option is C 1 Given, ^ 2 x 1 sin^ 2 x =^2x cosec^2x =^2x (1+^2x) ..........[Since #160;cosec^2x=1+^2x ] = 1 ...

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Trigonometric Identity- 2

Find the valu...

Question

Find the value of $c o t^{2} x - \frac{1}{s i n^{2} x}$

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\frac{1}{2}

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\int \frac{d x}{s i n 2 x \sqrt{{c o t}^{2} x - 1}}

0

x

\frac{π}{4}

\frac{d}{d x} \sqrt{\frac{1 - sin 2 x}{1 + sin 2 x}}

(0 < x < \frac{π}{2})

\frac{\sqrt{1 - {cos}^{2} x}}{sin x} + \frac{\sqrt{1 - {sin}^{2} x}}{cos x}

0 < x < \frac{π}{2}

\frac{1}{t a n^{2} x} - \frac{1}{s i n^{2} x}

| c o t (2 x - \frac{π}{2}) | = \frac{1}{c o s^{2} 2 x} - 1.

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