Find the value of 10- - 3 10-

cosec 10 √(3) sec 10 =1/sin10 √(3)/cos 10 = cos 10 √(3)sin 10/sin 10 cos 10=2[cos 10 √(3)sin 10/2 sin 10 cos 10] =4[1/2cos 10 √(3)/2sin 10/sin 20 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Circular Measurement of Angle

Find the valu...

Question

Find the value of $csc 10^{\circ} - \sqrt{3} sec 10^{\circ}$

Open in App

Solution

Suggest Corrections

Similar questions

2^{10}

3^{10}

x

(\frac{8}{9})^{5} = \frac{8^{5}}{x}

{(\frac{1 + \sqrt{3} i}{1 - i \sqrt{3}})}^{10} - {(\frac{1 - \sqrt{3} i}{1 + i \sqrt{3}})}^{10}

c o sec 10^{\circ} - \sqrt{} 3 sec 10^{\circ}

\sqrt{2} = 1.414, \sqrt{3} = 1.732, \sqrt{5} = 2.236

\sqrt{10} = 3.162

\frac{2}{\sqrt{3}}

\frac{3}{\sqrt{10}}

\frac{\sqrt{5} + 1}{\sqrt{2}}

\frac{\sqrt{10} + \sqrt{15}}{\sqrt{2}}

\frac{2 + \sqrt{3}}{3}

\frac{\sqrt{2} - 1}{\sqrt{5}}

Join BYJU'S Learning Program