Question

Find the value of cube root of the number $6860$. (Round off your number to the nearest hundredth)

• A. $19.003$
• B. $19.00$
• C. $19.32$
• D. $19.008$

Answer 1

The correct option is B $19.00$

We need to find value of $\sqrt[3]{36860}$
Take, $n=6860$, choose any starting value of $x$.
So, ${19}^3$ is $6859<6860$
So, $x=19$
$x_{\text{next}}=$ $\frac{2}{3}x+\frac{n}{3x^2}$
$x_{\text{next}}=$ $\frac{2}{3}19+\frac{6860}{3\times {19}^2}$
$x_{\text{next}}=19.00085$ ....(1)
So, the approximate value of $\sqrt[3]{36860}$ nearest hundredth place is $19.00$.