Find the value of current $i$ in the circuit. (Consider diodes to be ideal.)

1 A

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2 A

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3 A

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4 A

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Solution

The correct option is A $1 A$

We can see that the diode $D_{1}$ is in forward bias and $D_{2}$ is in reverse bias,
Therefore, $D_{1}$ will conduct whereas $D_{2}$ will not conduct current.

$∴ i = \frac{V}{R} = \frac{4 V}{4 Ω} = 1 A$

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Find the value of current i in the circuit. (Consider diodes to be ideal.)

The correct option is A 1 A We can see that the diode D1 is in forward bias and D2 is in reverse bias, Therefore, D1 will conduct whereas D2 will not conduct current. ∴i=VR=4 V4 Ω=1 A

Find the value of current $i$ in the circuit. (Consider diodes to be ideal.)

The correct option is A $1 A$

We can see that the diode $D_{1}$ is in forward bias and $D_{2}$ is in reverse bias,
Therefore, $D_{1}$ will conduct whereas $D_{2}$ will not conduct current.

$∴ i = \frac{V}{R} = \frac{4 V}{4 Ω} = 1 A$