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Question

Find the value of ΔH for the reaction, Fe2O3(s)+3CO2(g)2Fe(s)+3CO2(g).

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Solution

The given reaction is:

Fe2O3(s)+3CO(g)2Fe(s)+3CO2(g)


The value of ΔHf,Fe2O3(s)=825.50 kJ/mol

The value of ΔHf,CO(g)=110.53 kJ/mol

The value of ΔHf,CO2(g)=393.52 kJ/mol


The enthalpy of a reaction is given by

ΔH=vpΔHf,pvrΔHf,p

where, vp is the stoichiometric coefficient of the product an the reactant;

ΔHf is the standard enthalpy of formation of a substance.


Putting the values of ΔHf for each compound in the given reaction, we can calculate the enthalpy of formation for the reaction as follows :

ΔH=[2×0+3×(393.52)][1×(825.50)+3×(110.53)]

ΔH=(01180.56+825.50+331.59) kJ/mol

ΔH=23.47 kJ/mol


Therefore, the value of ΔH for the given reaction is 23.47 kJ/mol.



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