You visited us 1 times! Enjoying our articles? Unlock Full Access!

1st Law of Thermodynamics

Q=50∘

Question

Find the value of \(\Delta U\).

\( K_{Q=50 J } \quad 30 J \)

+20 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

-80 J

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

+80 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

-20 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B -80 J
Take a minute and try to get this on your own. Then move on the next video for the explanation.

Suggest Corrections

Similar questions

P = 50 \sum r = 1 \frac{^{50 + r} C_{r} (2 r - 1)}{^{50} C_{r} (50 + r)}, Q = 50 \sum r = 0 (^{50} C_{r})^{2}

R = 100 \sum r = 0 (- 1)^{r} (^{100} C_{r})^{2}

A B | | C D, ∠ A P Q = 50^{\circ} a n d ∠ P R D = 127^{\circ}

p = \sqrt{32} - \sqrt{24}

q = \sqrt{50} - \sqrt{48}

∆

∠

∠

°

Join BYJU'S Learning Program