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Byju's Answer
Standard IX
Mathematics
Rationalisation
Find the valu...
Question
Find the value of
1
√
5
−
√
5
−
√
24
+
1
√
5
−
√
5
+
√
24
.
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Solution
Now,
1
√
5
−
√
5
−
√
24
+
1
√
5
−
√
5
+
√
24
Let's rationalize the denominator of both the terms, we get
=
√
5
+
√
5
−
√
24
(
√
5
)
2
−
(
√
5
−
√
24
)
2
+
√
5
+
√
5
+
√
24
(
√
5
)
2
−
(
√
5
+
√
24
)
2
=
1
24
(
√
5
+
√
5
−
√
24
−
√
5
−
√
5
+
√
24
)
=
1
24
(
√
5
−
√
24
−
√
5
+
√
24
)
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0
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