Find the value of- 230 - 229 - 228231 - 230 - 229

2^30+2^29+2^2812^31+2^30 2^29=2^28(1+2+4)2^29(4+2 1) =72×5 =710 = 0.7 ...

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Division of a Polynomial by a Monomial

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Question

Find the value of: $\frac{2^{30} + 2^{29} + 2^{28}}{2^{31} + 2^{30} - 2^{29}}$

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Solution

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\frac{2^{30} + 2^{29} + 2^{28}}{2^{31} + 2^{30} - 2^{29}} = \frac{7}{10}

\frac{3^{30} + 3^{29} + 3^{25}}{3^{31} + 3^{30} - 3^{29}} + \frac{2^{30} + 2^{29} + 2^{25}}{2^{31} + 2^{30} - 2^{29}}

_{92}^{230} U \to n_{92}^{229} U

_{92}^{230} U \to p +_{91}^{229} Pa

_{92}^{230} U) = 230.033927 u,

_{92}^{229} U) = 229.03349 u, m_{n} = 1.008665 u,

_{91}^{229} Pa) = 229.032089, m_{p} = 1.007825, 1 a m u = 931.5

_{92}^{230} U

M (_{92}^{230} U) = 230.033927 a m u, M (_{92}^{230} U) = 229.033496 a m u, M (_{92}^{229} P a) = 229.032089 a m u, m (n) = 1.008665 a m u, m (p) = 1.007825 a m u

_{92}^{230} U \to n +_{92}^{229} U

_{92}^{230} U \to p +_{91}^{229} P a

M (_{92}^{230} U) = 230.033927 u M (_{92}^{229} U) = 229.03349 u

m_{n} = 1.008665 u

m_{p} = 1.007825

1 a m u = 931.5 M e V

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