Question

Find the value of $\frac{2022!\times 0!}{2021!}.$

• A. $0$
• B. $2021$
• C. $2022$
• D. None of the above

Answer 1

The correct option is C $2022$

$\underset{–}{\text{Need to Find}:}$
The value of $\frac{2022!\times 0!}{2021!}$

$\frac{2022!\times 0!}{2021!}$

$=\frac{2022\times 2021!\times 0!}{2021!}[\because n!=n\times (n-1)!]$

$=2022\times 1$ $(\because 0!=1)$

$=2022$

Therefore, option (c.) is the correct choice.