Question

Find the value of $\frac{{38}^2-{22}^2}{16}$ using a suitable identity.

• A. 80
• B. 70
• C. 60
• D. 90

Answer 1

The correct option is C 60

Since $(a^2-b^2)=(a+b)(a+b$), therefore
${38}^2-{22}^2=(38-22)(38+22)=16\times 60$

So, $\frac{{38}^2-{22}^2}{16}=\frac{16\times 60}{16}=60$