Question

Find the value of:
$\frac{5\left(26\right)!+\left(27\right)!}{4\left(27!\right)-8\left(26\right)!}$

Answer 1

$\frac{5(26!)+27!}{4\left(27\right)!-8\left(26\right)!}=\frac{5\left(26\right)!+27\left(26\right)!}{4\times 27\left(26\right)!-8\left(26\right)!}$

$=\frac{(5+27)\left(26\right)!}{(4\times 27-8)\left(26\right)!}=\frac{5+27}{4\times 27-8}$

$=\frac{32}{108-8}=\frac{32}{100}$

$=\frac{8}{25}$