Question

Find the value of $\frac{8a^3{b}^6}{1000}$ for $a=5$ and $b=4$.

Answer 1

Given that:

$a=5,b=4$

$\frac{8a^3{b}^6}{1000}$

$=\frac{8\times 5^3\times 4^6}{1000}$ (substituting the values of $a$ and $b$)

$=\frac{8\times (5\times 4{)}^3\times 4^3}{1000}$ [Since $a^{\left(bc\right)}=a^b{a}^c$ and $a^c{b}^c=(ab{)}^c$]

$=\frac{8\times 8000\times 4^3}{1000}$

$=64\times 4^3$

$=4^3\times 4^3$

$=4^6$

Hence, the value is $4^6$