Question

Find the value of $\frac{a-2}{3}+\frac{a-1}{2}+\frac{a+5}{6}=1$

Answer 1

$\frac{a-2}{3}+\frac{a-1}{2}+\frac{a+5}{6}=1$

$\Rightarrow \frac{2(a-2)}{3}+\frac{3(a-1)}{2}+\frac{a+5}{6}=1$

$\Rightarrow \frac{2a-4}{6}+\frac{3a-3}{6}+\frac{a+5}{6}=1$

$\Rightarrow \frac{2a-4+3a-3+a+5}{6}=1$

$\Rightarrow \frac{6a-2}{6}=1$

$\Rightarrow 6a-2=6$

$\Rightarrow 6a=6+2=8$

$\Rightarrow a=\frac{8}{6}=\frac{4}{3}$