Question

Find the value of $\frac{\left(y^3-5y^2\right)}{y}\times \left(y-1\right)$

Answer 1

$\left(y^3-5y^2\right)÷y\times \left(y-1\right)$

$=y^2\left(y-5\right)\times \frac{1}{y}\times \left(y-1\right)$

$=\left(y-5\right)\times y\times \left(y-1\right)$\

$=y\left(y^2-6y+5\right)$