Question

Find the value of $\frac{\log \sqrt{27}+\log 8-\log \sqrt{1000}}{\log 1.2}$

Answer 1

$\frac{\log \sqrt{27}+\log 8-\log \sqrt{1000}}{\log 1.2}=\frac{\frac{3}{2}\log 3+3\log 2-\frac{3}{2}\log 10}{\log 1.2}=\frac{3}{2}\times \frac{\log 1.2}{\log 1.2}=\frac{3}{2}$