Question

Find the value of discriminant $\left(\Delta \right)$ for the quadratic equation: $x^2+3x+1=0$.

Answer 1

Discriminant of $a{x}^2+bx+c=0$ is given by $\Delta =b^2-4ac$

Here $a=1,b=3,c=1$

$\therefore \Delta =3^2-4\cdot 1\cdot 1=9-4=5$